Thursday, 12 June 2014 12:48


Additional Info

  • ID Code: C6-16
  • Purpose: Show that the friction force depends linearly on the normal component of the applied force.
  • Description: 1. Put 5-kg mass on left pan of balance and the blue block on the right pan. Add to the right pan 1 kg plus additional masses from the weight set to achieve balance.
    2. Place block on lecture table with the additional right-pan weights on top of it. (Together they have a mass of 5 kg.)
    3. Determine the force of friction by pulling the box with its weights across the lecture table using twine and the spring scale.
    Place additional 5 kg mass on block and repeat. Repeat with block on edge. Typically about 13 Newtons is required to pull the 5 kg combination. This gives a coefficient of friction mu=13/(5X9.8)=0.26, which is roughly what is expected for wood on wood. The difference between static an sliding friction is readily visible.
  • Availability: Available
  • Loc codes: C6, ME1
Read 2309 times Last modified on Wednesday, 19 May 2021 15:26
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