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  • B2-04: VERTICAL FORCES - FOUR SPRING SCALES

    B2-04
    Show addition of forces along a line
    A set of four spring scales are hung from a stand. Each scale shows the total weight of those hanging below it plus any force exerted downward on the lower scale. The bottom scale measures its own weight, about 3 Newtons. In the picture above, a downward force of 9 Newtons is being exerted by Jack's hand at the bottom of the picture, so the scales read (bottom to top) 12N, 12N, 15N, and 18N.
    ME1, FS2
  • B2-11: EQUILIBRIUM OF FORCES - OHAUS PROJECTION

    B2-11
    Demonstrate equilibrium of forces
    Forces are applied by hanging arbitrary weights on hangers over pulleys. The ring to which the forces are applied will stabilize symmetrically about the center pin when the forces are in equilibrium. Forces can be applied at arbitrary angles by rotating the pulley arms. The photographs above show details of the center of the force table and the system displayed using an overhead projector.

    Note that there are three arms over which weights may be hung, and thus a maximum of three vectors can be summed.

    B2

     

    Close-up of center of platform, and overhead projector display.

  • B2-12: EQUILIBRIUM OF FORCES - BOARD BACKGROUND

    B2-12
    Demonstrate equilibrium of forces
    Three forces are set up in static equilibrium. The lower spring scale is modified so that it measures its own weight plus the weight hanging on the hook below. Upper spring scales are calibrated to read zero when the connecting arms are in place and the lower scale is removed. A large protractor can be used to measure angles.
    FS1
  • B2-14: SUM OF FORCES - LARGE ROPE VERSION

    B2-14
    Develop a feel for equilibrium of forces on a large scale
    Three or four people can pull ropes in various directions to find combinations of forces and directions that result in equilibrium.
    B2
  • B2-21: CONCEPT OF TORQUE - TORSIONAL CHAIR

    B2-21
    Introduce the concept of torque

    A rigid scale is attached to the torsional chair (with its internal coil spring attached to provide a countering force). An arbitrary force (measured by the spring scale) can be exerted at an arbitrary angle (measured by the protractor) at an arbitrary distance from the center of the chair (measured by the scale) to produce some arbitrary rotation of the chair against its restoring spring. Equal torques can be applied in several different ways, or torques can be scaled by changing one or more of the variables. Measurements are good to about ten percent.

    The photographs above show the chair being rotated about 180 degrees by an external torque, which is created by a force perpendicular to the radius vector (center) or at an angle of 45 gegrees with respect to the radius vector (right).

    Note that this demonstration and demonstrations B2-22 and B2-32 use many of the same components.

    FS0, OS0, B2

      

  • B2-31: EQUILIBRIUM OF TORQUES - WHEELS AND AXLES

    B2-31
    Demonstrate equilibrium of torques

    Two wheel and axle assemblies are provided. For each, there are cylinders of smaller radius r and larger radius R. A smaller weight m is suspended from a string wrapped around the larger radius R, and a larger weight M suspended from the smaller radius r. For equilibrium of torques:

    mR = Mr.

    On this model, radius ratios of 2:1 and 4:1 are available. A set of additional masses can be provided to vary the load.
    FS2
  • B2-33: EQUILIBRIUM OF TORQUES - SMALL

    B2-33
    Demonstrate equilibrium of torques

    Weights are hung at points along a 50cm scale to balance torques about the pivot at the center of the scale.

    B2

    stat

  • B2-34: EQUILIBRIUM OF TORQUES - ANGLE BRACKET

    B2-34
    Verify the equation for torques when the center of mass is outside the object

    A bracket is bent into a right triangle with arms of length a and 2a, and suspended from the end of the small arm as photographed. What is the angle of repose r of the small arm with the vertical, at equilibrium?


    From the equation of torques, w1 x1 = w2 x2,


    where: w1= mg and x1= a/2 sin r,


    also: w2 = 2mg and x2 = a cos r - a sin r)


    From these, tan r = 4/5, and r = 38.66 degrees.

    B2
  • B2-35: EQUILIBRIUM OF TORQUES ON METERSTICK

    B2-35
    Demonstrate equilibrium of torques

    Balance the meter stick on your two index fingers, with one finger initially at one end and the other finger about one-quarter of the way from the other end. Slide your fingers together (moving either one or the other or both). Your fingers will always end up together directly under the center of mass.

    Try different starting points. Try adding a 100 gram weight onto either end. Try greasing your finger. It always works. Ask your students what they think will happen before doing the original experiment. Ask them again after adding a weight to one end.

    B2
  • B2-36: EQUILIBRIUM OF TORQUES ON METERSTICK - ROTATORS

    B2-36
    Demonstrate equilibrium of torques

    Balance the meter stick ASYMMETRICALLY on the two rotators, and start the rotators in motion. Then balance the meter stick as close to SYMMETRICALLY as you can and start the rotators. It will always fall off if the rotators rotate outward, and will always end up balanced with the CM in the center if the rotators rotate inward. Which direction it moves depends on very small asymmetries!! Click the links below for several cases:


    Rotators rotate inward, meter stick starts asymmetrically balanced.

    Rotators rotate outward, meter stick starts asymmetrically balanced.

    Rotators rotate outward, meter stick starts symmetrically balanced and falls to the left.

    Rotators rotate outward, meter stick starts symmetrically balanced and falls to the right.


    Try different starting points. Try adding a 100 gram weight onto either end. (Please ask for the weight so we do not overlook it.) It always works. Ask your students what they think will happen before doing the original experiment. Ask them again after adding a weight to one side.

    B2

    st

  • B2-42: ARM MODEL

    B2-42
    Model the forces occurring in the arm

    Photograph at the top shows arm model in neutral force configuration

    Force applied by the biceps (lower left), pulling up with the hand: Apply 2.5 kg to the biceps cable to support the unloaded forearm. The forearm may be kept at equilibrium by the simultaneous addition of masses in the ratio of 10:1 at the biceps and at the hand. The torques are balanced almost independently of the angular position of the arm.

    Force applied to the triceps (lower right), pushing down with the hand: Hang the spring scale between the top hook and the hand hook, and attach the hanger to the triceps cable. Add masses to the hanger to determine how much force in the triceps is necessary to push down with the force read on the scale.

    FS2

     

  • B2-43: CRANE BOOM

    B2-43
    Demonstrate a crane boom
    The three configurations pictured may be readily set up and analyzed. The dynamometer measures tension in the rope; an internal spring scale measures the compression in the boom.

     

  • B3-01: LEVER AND LOADED WAGON

    B3-01
    Demonstrate the mechanical advantage of a lever
    The front of the cart can be lifted with the fulcrum one or two feet from the end of the lever. Even with one or two students on the cart, the cart can easily be lifted with a moderate downward force on the lever.
    FS1
  • B3-02: LEVERS - THREE CLASSES

    B3-02
    Demonstrate the three classes of levers

    Referring to the three photographs above:

    First class lever (top): the pivot is between the load and the applied force (push down with hand or pull down with spring scale at left in photo).

    Second class lever (lower left): the load is between the pivot and the applied force.

    Third class lever (lower right): the applied force is between the load and the pivot.



    Note: Look this over before class; you must change around the various components during the lecture.
    ME1, OS0

     

  • B3-11: PULLEY - HUMAN LIFT

    B3-11
    Demonstrate the mechanical advantage of a pulley (Requires additional set-up time)

    A pulley is attached to a hook about ten feet above the floor. The subject is able to raise his or her body off the floor by exerting a force equal to one-half of his or her weight. Use gloves to protect hands from rope burn.

    Noose must be looped below arms. Standing on rope loop can cause you to flip, leading to possible head injury. DO NOT STAND ON ROPE!

    Note that due to height limitations, this demonstration is only available in rooms 1410 and 1412.

    Note that this demonstration requires additional setup time of at least 24 hours. Please contact the facility to make arrangements for this demonstration.

  • B3-14: EQUILIBRIUM PARADOX - SCALES AND PULLEY

    B3-14
    Counterintuitive demonstration involving pulley system
    A frame containing the pulley and the lower scale hangs from the upper scale as photographed. The initial weight of the lower scale, pulley, and frame together is about 5 Newtons, as read on the upper scale; initially the lower scale reads zero. The difference in resultant force due to the pulley can be observed from the difference in the change of the two scales.
    FS2

     

  • B3-15: FOOL'S TACKLE

    B3-15
    Illustrate analysis of forces in a pulley system

    In the pulley system photographed, the weight hanging from the free pulley is W, and the pulleys are approximately massless. The rope will be pulled at its free end, and passes over the free pulley, under the pulley attached to the weight, and back over the fixed pulley to support the free pulley. With what force F must you pull on the free end of the rope to just barely lift weight W off the ground: W, W/2, W/3, or "other?"


    Let your students guess before having one of them try to lift weight W by pulling on the end of the rope. Note that this is a "gag" demonstration! The reasons why the system stays set up as photographed are (1) the rope is pinned to the "free" pulley, and (2) the rope loop is stretched tightly between the upper and lower pulleys, so that the friction prevents the weight of the "free" pulley from falling. A video of the "action" is available below.

    This result can be determined in about twenty seconds as follows: Pulling on the free end with a force F causes a tension F throughout the rope. The result is a force 2F downward and F upward on the "free" pulley, causing it to move downward.

    FS2
  • B4-04: SPRING AND STRING THING

    B4-04
    Illustrate series and parallel springs in a counterintuitive way.

    Two springs connected in series support a weight. Strings slightly longer than the springs are connected in parallel with each spring, as photographed. The connecting wire loop between the two springs is then removed, forming two separate parallel routes, each consisting of a spring and a string in series. Comparing the final configuration with the initial configuration, will the weight be higher, lower, or at the same vertical position?

    The pictures above show the system in its initial and final configurations, as well as in detail of how the springs and strings are coupled at the center.

    This demonstration is an analog to paradoxical behavior in complex series/parallel arrangements for other mechanical, hydraulic, and electrical systems. Perhaps the most notable is Braess' paradox for traffic flow. In certain types of congested traffic flow situations, opening an additional new route between two points may actually increase the average time taken to travel between the two points.

    FS2

    b4-04a b4-04b

  • B4-11: ELASTIC LIMIT OF RUBBER BAND

    B4-11
    Demonstrate Hooke's law and elastic limit.
    Load small weights to demonstrate Hooke's law. Hanging a few kilograms from the rubber band exceeds its elastic limit.
    FS2, ME1

    b4-11a

  • B4-14: ELASTIC LIMIT OF WIRE

    B4-14
    Demonstrate the variation in tensile strength with wire diameter.
    Two wires are used: 24 AWG, 0.474 mm diameter, and 20 AWG, 0.786 mm diameter. The ratio of tension required to break two wires is proportional to the square of their diameters, for this case F2 / F1 = 2.75. The two wires can be broken, the required tensions read off the attached spring scale, and the ratio calculated.
    B4