Each week, we highlight one of our many demonstrations by asking a physics question relevant to the topic designed to be illustrated. This not only challenges audiences to carefully examine their previously held views on physics, but also provides suggestions for teachers looking to use these demonstrations in their own classrooms.

Be sure to check back each week for the solutions to the previous weeks' questions and for newest question of the week.

  • Question of the Week Archive
  • Question of the Week 4/27 - 5/1
  • Question of the Week 4/20 -4/24 with Answer
  • Question of the Week 4/13 - 4/17 with Answer
  • Question of the Week 4/6 - 4/10 With Answer

Missed one of our older Question of the Weeks? Click here to access our archive.

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An experimenter walks briskly forwardwith a ball in one hand, and attempts to release the ball so that it will fall into a bucket, as shown in the photo below:

 c2 28

The question is where one must release the ball in order for it to fall into the bucket. In the photograph the ball has been released and is falling, but whether it will fall into the bucket is not certain. As you walk along, must you release the ball before or after the position shown here? Must you wait until your hand is directly above the bucket, or slightly beyond that point, due to the effect of conservation of momentum between your hand and the ball at the time when it is released?

In order for the ball to fall into the bucket, you must release it:

  • (a) somewhere to the left of where the scientist is in the picture.
  • (b) somewhere to the right of where the scientist is in the picture, but not as far as the bucket.
  • (c) when your hand is directly above the bucket.
  • (d) when your hand is just past the center of the bucket.

After May 1, click Read More for the answer.


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Shown in the photographs below are the front and the top view of two straight wooden rods, one red and one blue. They are mounted between two plastic plates, not shown.


 a1 43  a1 43a
                                       Front                                      Top 

The question this week involves what we can say about this geometry. In particular, are the two rods might be touching each other at any point?

The two rods:

  • (a) are definitely touching at some point.
  • (b) are definitely not touching at any point.
  • (c) may or may not be touching; it is impossible to say.

After April 24th, click Read More for the answer.

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Five identical light bulbs, labeled A through E, are connected to a voltage source in the series/parallel circuit shown below. Any or all of the bulbs can be placed into the circuit by turning ON the switches that are wired in series with the particular bulbs. In the photograph none of the switches have been closed so all of the bulbs are off.

 k6 12

The question this week involves how brightly each of the light bulbs will glow when ALL of them are inserted into the circuit by turning their switches on.

For the "answer" this week, write down a list of the bulbs in order of their brightness, from brightest to dimmest, for example:

E > D > B > A > C;

or A > B = C > D > E;

or perhaps C > D = E > A = B;

or any number of other possible combinations.


What will the sequence of brightness be?

For the answer, click Read More after April 17, 2015.

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The apparatus for this week's question consists of a rod at the bottom of which there is a fixed circular mass. The rod pivots above this mass at a fixed point and is free to oscillate from side to side. Above the pivot point there is moveable trapezoidal mass, which can be adjusted either higher or lower. Catch a video of it in action by clicking your mouse on the photograph below.


Notice how the adjustable mass is very close to the pivot point.

And now the question: Suppose the mass were adjusted further upwards, away from the pivot point (pictured below). How would the of frequency of oscillation change?


 There should be two parts to a good answer: What will happen, and why?

  • (a) The frequency will not change; the ticking machine will oscillate the same.
  • (b) The frequency will increase (i.e. the machine will tick faster). perhaps the torque exerted by the moveable mass will be greater, the effect would be much like moving a person further down a teeter-totter; the further the person is away, the more quickly rod will accelerate.
  • (c) The frequency will decrease (i.e. tick slower). Perhaps the torque exerted by the moveable mass will be less, and therefore the effect would be like moving a person closer in on a teeter-totter. Less torque, less acceleration.
  • (d) Other (you must explain).

 Click Read More for the answer after April 10, 2015

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